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18 changes: 15 additions & 3 deletions Sprint-2/1-key-errors/0.js
Original file line number Diff line number Diff line change
@@ -1,5 +1,10 @@
// Predict and explain first...
// =============> write your prediction here
// The error in the code occurs because the variable 'str' is being declared twice within the same scope.
// The first declaration is in the function parameter, and the second declaration is inside the function body.
// This causes a syntax error because JavaScript does not allow redeclaration of variables in the same scope using 'Let'.
// To fix this error, we can simply remove the 'Let' keyword from the second declaration of 'str' inside the function body.
// The correction would be to assign the new variable without redeclaration, like this: 'str = `${str[0].toUpperCase()}${str.slice(1)}`;'.
// This way, we are reassigning the value of 'str' without trying to declare it again.

// call the function capitalise with a string input
// interpret the error message and figure out why an error is occurring
Expand All @@ -9,5 +14,12 @@ function capitalise(str) {
return str;
}

// =============> write your explanation here
// =============> write your new code here
// The error in the code occurs because the variable 'str' is being declared twice within the same scope.
// The first declaration is in the function parameter, and the second declaration is inside the function body.
// This causes a syntax error because JavaScript does not allow redeclaration of variables in the same scope using 'Let'.
// To fix this error, I can rename the variable inside the function body to something else, like 'caps', to avoid redeclaration.

function capitalise(str) {
let caps = `${str[0].toUpperCase()}${str.slice(1)}`;
return caps;
}
12 changes: 9 additions & 3 deletions Sprint-2/1-key-errors/1.js
Original file line number Diff line number Diff line change
@@ -1,7 +1,7 @@
// Predict and explain first...

// Why will an error occur when this program runs?
// =============> write your prediction here
// Declaring a variable with the same name as the function parameter in the function body causes a SyntaxError.

// Try playing computer with the example to work out what is going on

Expand All @@ -14,7 +14,13 @@ function convertToPercentage(decimalNumber) {

console.log(decimalNumber);

// =============> write your explanation here
// After running the code, the following error message was displayed:
// Uncaught SyntaxError: Identifier 'decimalNumber' has already been declared

// Finally, correct the code to fix the problem
// =============> write your new code here
// function convertToPercentage(decimalNumber) {
// const percentage = `${decimalNumber * 100}%`;
// return percentage;
// }

// console.log(convertToPercentage(0.5));
13 changes: 7 additions & 6 deletions Sprint-2/1-key-errors/2.js
Original file line number Diff line number Diff line change
Expand Up @@ -3,18 +3,19 @@

// this function should square any number but instead we're going to get an error

// =============> write your prediction of the error here
// The error occurs because 3 is used as a function parameter.
// Parameters must be variable names, whereas values are passed as arguments when the function is called.

function square(3) {
return num * num;
}

// =============> write the error message here
// Uncaught SyntaxError: Unexpected number

// =============> explain this error message here
// The parser evaluates the code as a SyntaxError before execution because a value cannot be used as a parameter name in JavaScript.

// Finally, correct the code to fix the problem

// =============> write your new code here


// function square(num) {
// return num * num;
// }
12 changes: 9 additions & 3 deletions Sprint-2/2-mandatory-debug/0.js
Original file line number Diff line number Diff line change
@@ -1,14 +1,20 @@
// Predict and explain first...

// =============> write your prediction here
// The result of multiplying 10 and 32 is expected to be undefined because the multiply() function does not return the result.
// It only prints it using console.log().

function multiply(a, b) {
console.log(a * b);
}

console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);

// =============> write your explanation here
// After running the code, the result of multiplying 10 and 32 is undefined indeed.
// The problem occurs because the function has no return statement to send a value back to where the function was called.

// Finally, correct the code to fix the problem
// =============> write your new code here
// function multiply(a, b) {
// return a * b;
// }

// console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);
12 changes: 9 additions & 3 deletions Sprint-2/2-mandatory-debug/1.js
Original file line number Diff line number Diff line change
@@ -1,5 +1,6 @@
// Predict and explain first...
// =============> write your prediction here
// The issue is that return is on one line and a + b is on the next.
// Therefore, a + b is never returned.

function sum(a, b) {
return;
Expand All @@ -8,6 +9,11 @@ function sum(a, b) {

console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);

// =============> write your explanation here
// After running the code, the sum of 10 and 32 is undefined.
// JavaScript inserts a semicolon after return when a + b is placed on the next line.
// This causes the function to return before calculating the sum.

// Finally, correct the code to fix the problem
// =============> write your new code here
// function sum(a, b) {
// return a + b;
// }
23 changes: 18 additions & 5 deletions Sprint-2/2-mandatory-debug/2.js
Original file line number Diff line number Diff line change
@@ -1,7 +1,7 @@
// Predict and explain first...

// Predict the output of the following code:
// =============> Write your prediction here
// I believe that in each case, the output will be the last digit of 103, which is 3.

const num = 103;

Expand All @@ -14,11 +14,24 @@ console.log(`The last digit of 105 is ${getLastDigit(105)}`);
console.log(`The last digit of 806 is ${getLastDigit(806)}`);

// Now run the code and compare the output to your prediction
// =============> write the output here
// The last digit of 42 is 3
// The last digit of 105 is 3
// The last digit of 806 is 3

// Explain why the output is the way it is
// =============> write your explanation here
// The function getLastDigit() does not accept a parameter.
// Consequently, it always uses the global variable num, whose value is 103.

// Finally, correct the code to fix the problem
// =============> write your new code here
// const num = 103;
// function getLastDigit(num) {
// return num.toString().slice(-1);
// }

// console.log(`The last digit of 42 is ${getLastDigit(42)}`);
// console.log(`The last digit of 105 is ${getLastDigit(105)}`);
// console.log(`The last digit of 806 is ${getLastDigit(806)}`);

// This program should tell the user the last digit of each number.
// Explain why getLastDigit is not working properly - correct the problem
// getLastDigit() is not working properly because it always uses the global num variable (103).
// I added num as a parameter so that the function can accept the value passed as an argument.
7 changes: 5 additions & 2 deletions Sprint-2/3-mandatory-implement/1-bmi.js
Original file line number Diff line number Diff line change
Expand Up @@ -15,5 +15,8 @@
// It should return their Body Mass Index to 1 decimal place

function calculateBMI(weight, height) {
// return the BMI of someone based off their weight and height
}
let bmi = weight / (height * height);
return bmi.toFixed(1);
}

console.log(calculateBMI(70, 1.73));
6 changes: 6 additions & 0 deletions Sprint-2/3-mandatory-implement/2-cases.js
Original file line number Diff line number Diff line change
Expand Up @@ -14,3 +14,9 @@
// You will need to come up with an appropriate name for the function
// Use the MDN string documentation to help you find a solution
// This might help https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/toUpperCase
function toUpperSnakeCase(input) {
return input.toUpperCase().replaceAll(" ", "_");
}

console.log(toUpperSnakeCase("hello there"));
console.log(toUpperSnakeCase("lord of the rings"));
23 changes: 23 additions & 0 deletions Sprint-2/3-mandatory-implement/3-to-pounds.js
Original file line number Diff line number Diff line change
Expand Up @@ -4,3 +4,26 @@
// You will need to declare a function called toPounds with an appropriately named parameter.

// You should call this function a number of times to check it works for different inputs
function toPounds(penceString) {
const penceStringWithoutTrailingP = penceString.substring(
0,
penceString.length - 1
);

const paddedPenceNumberString = penceStringWithoutTrailingP.padStart(3, "0");

const pounds = paddedPenceNumberString.substring(
0,
paddedPenceNumberString.length - 2
);

const pence = paddedPenceNumberString
.substring(paddedPenceNumberString.length - 2)
.padEnd(2, "0");

return `£${pounds}.${pence}`;
}

console.log(toPounds("399p"));
console.log(toPounds("5p"));
console.log(toPounds("1200p"));
17 changes: 9 additions & 8 deletions Sprint-2/4-mandatory-interpret/time-format.js
Original file line number Diff line number Diff line change
Expand Up @@ -21,18 +21,19 @@ function formatTimeDisplay(seconds) {
// Questions

// a) When formatTimeDisplay is called how many times will pad be called?
// =============> write your answer here
// pad() is called 3 times because it is used once for hours, once for minutes, and once for seconds.

// Call formatTimeDisplay with an input of 61, now answer the following:

// b) What is the value assigned to num when pad is called for the first time?
// =============> write your answer here
// Because the first call to pad() is pad(totalHours), and formatTimeDisplay(61) calculates totalHours as 0, the value passed to pad() as num is 0.

// c) What is the return value of pad is called for the first time?
// =============> write your answer here
// c) What is the return value of pad when called for the first time?
// When pad() is called for the first time, num is 0 because totalHours is 0.
// The function converts it to a string and adds a leading zero, so the return value is "00".

// d) What is the value assigned to num when pad is called for the last time in this program? Explain your answer
// =============> write your answer here
// d) What is the value assigned to num when pad is called for the last time in this program? Explain your answer
// Because the last call to pad() is pad(remainingSeconds) and formatTimeDisplay(61) calculates remainingSeconds as 1 (61 % 60 = 1), the value passed into pad() as num is 1.

// e) What is the return value of pad when it is called for the last time in this program? Explain your answer
// =============> write your answer here
// e) What is the return value of pad when it is called for the last time in this program? Explain your answer
// The return value of pad() when it is called for the last time is "01" because num is 1, and the function pads numbers by adding a leading zero.
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